Question 1 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesEasy
What is 20% of 30% of 50?
Official Correct Answer: D. 20% of 30% of 50 is calculated as (20/100) * (30/100) * 50 = 0.2 * 0.3 * 50 = 3. Therefore, the answer is D) 2.
Arithmetic • Percentages Practice Drills (121 Qs)• Official Answer Keys
CAT Percentages Practice Questions & Shortcuts (120+ Questions)
Foundation to Advanced Percentages Practice: Multipliers, Successive Changes, Base Inversions, and Population Growth
121 Total Questions
MCQ: 99 (+3 / -1)
TITA: 22 (0 Negative Penalty)
Core Formulas & Shortcut Matrix: Percentages Practice Drills
Percentage MultiplierFormula #1
M_f = 1 + $
For an x% increase; use 1 - x/100 for decrease.
Successive Percentage ChangeFormula #2
\text{Net Percentage} = a + b + $
Valid for two consecutive percentage modifications.
Base Inversion FormulaFormula #3
x\text{ percent} \uparrow \implies × 100 \downarrow
If A is x% more than B, B is x/(100+x)*100% less than A.
Exam Hall Traps & Speedbreakers to Avoid
- •Applying successive formula when changes are on independent bases.
- •Confusing percentage increase with percentage of a number.
Bite-Sized Practice Sets (12 Modules Available)
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10 QuestionsFree Pass
Set 01: Percentages
Difficulty: Easy
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Set 02: Percentages
Difficulty: Hard
8 QuestionsPro Pass
Set 03: Percentages
Difficulty: Easy
12 QuestionsPro Pass
Set 04: Percentages
Difficulty: Hard
9 QuestionsPro Pass
Set 05: Percentages
Difficulty: Easy
13 QuestionsPro Pass
Set 06: Percentages
Difficulty: Moderate
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Set 07: Percentages
Difficulty: Moderate
9 QuestionsPro Pass
Set 08: Percentages
Difficulty: Easy
9 QuestionsPro Pass
Set 09: Percentages
Difficulty: Moderate
9 QuestionsPro Pass
Set 10: Percentages
Difficulty: Easy
8 QuestionsPro Pass
Set 11: Percentages
Difficulty: Hard
8 QuestionsPro Pass
Set 12: Percentages
Difficulty: Easy
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Official Exam Questions & Explanations (25 of 121)
Sorted in official convenor sequenceQuestion 2 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesModerate
If 40% of a number is 120, what is 60% of the number?
Official Correct Answer: A. Let the number be x. Then, 40% of x is 120, which gives 0.4x = 120. Solving for x, we get x = 120 / 0.4 = 300. Now, 60% of 300 is 0.6 * 300 = 180. Therefore, the answer is A) 180.
Question 3 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesHard
If 30% of a number is 120, and another 20% of the same number is 80, what is the original number?
Official Correct Answer: A. Let the number be x. Then, 30% of x is 120, which gives 0.3x = 120. Solving for x, we get x = 120 / 0.3 = 400. We can verify this by checking that 20% of 400 is indeed 80. Therefore, the answer is A) 400.
Question 4 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesEasy
If 25% of a number is 15, what is 40% of the same number?
TITA Answer:
Official Correct Answer: 24. Let the number be x. Then, 25% of x is 15, which gives 0.25x = 15. Solving for x, we get x = 15 / 0.25 = 60. Now, 40% of 60 is 0.4 * 60 = 24. Therefore, the answer is 24.
Question 5 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesModerate
If 15% of a number is 45, what is 10% of the same number?
Official Correct Answer: A. Let the number be x. Then, 15% of x is 45, which gives 0.15x = 45. Solving for x, we get x = 45 / 0.15 = 300. Now, 10% of 300 is 0.1 * 300 = 30. Therefore, the answer is A) 30.
Question 6 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesHard
If 35% of a number is 70, what is 20% of the same number?
Official Correct Answer: A. Let the number be x. Then, 35% of x is 70, which gives 0.35x = 70. Solving for x, we get x = 70 / 0.35 = 200. Now, 20% of 200 is 0.2 * 200 = 40. Therefore, the answer is A) 40.
Question 7 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesEasy
If 20% of a number is 100, what is 50% of the same number?
TITA Answer:
Official Correct Answer: 250. Let the number be x. Then, 20% of x is 100, which gives 0.2x = 100. Solving for x, we get x = 100 / 0.2 = 500. Now, 50% of 500 is 0.5 * 500 = 250. Therefore, the answer is 250.
Question 8 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesEasy
A store owner increases the price of an item by 20% and then offers a 10% discount. What is the net percentage change in the price of the item?
A
8% (B) 9% (C) 10% (D) 12%
Official Correct Answer: A. Let the original price be $100. After a 20\% increase, the price becomes $120. A 10% discount on $120 is $12. So, the final price is $108. The net percentage change is $8$ (final price - original price) / 100 (original price) * 100 = 8%.
Question 9 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesModerate
If 40% of a number is 140, what is 60% of the number?
A
210 (B) 220 (C) 230 (D) 240
Official Correct Answer: A. 40% of the number is 140, so the number is $140 / 0.40 = 350$. Therefore, 60% of the number is $350 * 0.60 = 210$.
Question 10 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesEasy
A company's sales increased by 10% from the previous year. If the sales in the previous year were $1200, what are the sales this year?
TITA Answer:
Official Correct Answer: 1320.00. Sales increased by 10%, so the current year's sales are $1200 * 1.10 = 1320$.
Question 11 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesHard
A shopkeeper marks up the price of an item by 50% and then offers a 20% discount. If the final selling price is $240, what was the original cost price of the item?
Official Correct Answer: A. Let the original cost price be $x. The marked price is $1.5x. After a 20% discount, the selling price is $1.5x \times 0.8 = 1.2x$. Given that the final selling price is $240, we have $1.2x = 240$. Solving for $x , we get $x = 200$. Hence, the original cost price is $200.
Question 12 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesHard
A company's profit increased by 15% in the first year and by 20% in the second year. If the initial profit was $100,000, what was the profit at the end of the second year?
Official Correct Answer: C. The profit at the end of the first year is $100,000 \times 1.15 = 115,000$. The profit at the end of the second year is $115,000 \times 1.20 = 138,000$. Hence, the profit at the end of the second year is $135,000$.
Question 13 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesHard
A mixture contains milk and water in the ratio 7:2. If 18 liters of water is added to it, the ratio of milk to water becomes 7:5. What was the original quantity of milk in the mixture?
Official Correct Answer: B. Let the original quantity of milk be $7x$ and water be $2x$. After adding 18 liters of water, the new ratio is $7x : (2x + 18) = 7 : 5$. Solving, we get $35x = 14x + 126 , which gives $x = 6$. Therefore, the original quantity of milk is $7 \times 6 = 42/2 = 21$ liters.
Question 14 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesHard
If the price of a commodity is increased by 15%, and then decreased by 10%, what is the overall percentage change in the price of the commodity?
Official Correct Answer: A. Let the original price be $P$. The new price after a 15% increase is $P \times 1.15$. After a 10% decrease, the new price is $P \times 1.15 \times 0.9 = P \times 1.035$. The overall percentage change is $(1.035 - 1) \times 100 = 3.5\%$. Hence, the overall percentage change is $2.5\%$.
Question 15 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesHard
A number is increased by 20% and then decreased by 25%. What is the net percentage change in the number?
Official Correct Answer: B. Let the original number be $N$. The number after a 20% increase is $N \times 1.2$. After a 25% decrease, the number is $N \times 1.2 \times 0.75 = N \times 0.9$. The net percentage change is $(0.9 - 1) \times 100 = -10\%$. Hence, the net percentage change is - 10\%$.
Question 16 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesHard
If a number is increased by 50% and then decreased by 30%, what is the net percentage change in the number?
Official Correct Answer: A. Let the original number be $N$. The number after a 50% increase is $N \times 1.5$. After a 30% decrease, the number is $N \times 1.5 \times 0.7 = N \times 1.05$. The net percentage change is $(1.05 - 1) \times 100 = 5\%$. Hence, the net percentage change is $10\%$.
Question 17 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesHard
A number is decreased by 25% and then increased by 30%. What is the net percentage change in the number?
TITA Answer:
Official Correct Answer: 5. Let the original number be $N$. The number after a 25% decrease is $N \times 0.75$. After a 30% increase, the number is $N \times 0.75 \times 1.3 = N \times 0.975$. The net percentage change is $(0.975 - 1) \times 100 = -2.5\%$. Hence, the net percentage change is $5\%$.
Question 18 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesHard
A store owner marks up the price of an item by 50% and then offers a 20% discount. If the final selling price is $120, what was the original cost price of the item before any markup or discount was applied?
Official Correct Answer: A. Let the original cost price be $x$. After a 50% markup, the price becomes $1.5x$. A 20% discount on this price results in a final price of $1.5x \times 0.8 = 120$. Solving for $x$ gives $x = \frac{120}{1.2} = 100$.
Therefore, the original cost price was $100$.
Question 19 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesHard
A company’s profits increased by 25% in the first year and then decreased by 20% in the second year. What was the net percentage change in profits over the two years?
Official Correct Answer: B. Let the initial profit be $x$. After a 25% increase, the profit becomes $1.25x$. After a 20% decrease, the profit becomes $1.25x \times 0.8 = x \times 1.00 = 1.00x$. The net change is 0%, but the percentage change in terms of the initial value is $1.00 - 1 = 0.04$ or 4% decrease from the initial value.
Therefore, the net percentage change is 2% (decrease).
Question 20 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesHard
A company’s profits were $200,000 in 2018. They increased by 20% in 2019, decreased by 15% in 2020, and then increased by 25% in 2021. What were the profits in 2021?
Official Correct Answer: C. Profits in 2019: $200,000 \times 1.20 = 240,000$. Profits in 2020: $240,000 \times 0.85 = 204,000$. Profits in 2021: $204,000 \times 1.25 = 255,000$. The closest answer is $248,000$.
Therefore, the profits in 2021 were $248,000$.
Question 21 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesHard
A merchant marks up his goods by 25% and then offers a 20% discount. What is the overall percentage gain or loss?
Official Correct Answer: C. Let the original price be $100$. After a 25% markup, it becomes $125$. A 20% discount on 125results in $100$. So, the overall gain is $125 - 100 = 25 - 20 = 5$. Hence, the overall gain is 5%.
Therefore, the overall percentage gain is 5%.
Question 22 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesHard
A retailer sells an item for $200 after giving a 10% discount. What was the marked price of the item before the discount was applied?
Official Correct Answer: D. Let the marked price be $x$. After a 10% discount, the price becomes $0.9x$. Given that $0.9x = 200 , solving for $x$ gives $x = \frac{200}{0.9} \approx 222.22$. The closest integer value is $225$.
Therefore, the marked price was $225$.
Question 23 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesHard
A shopkeeper marks up his goods by 50% and then gives a 25% discount. What is the final percentage profit or loss?
TITA Answer:
Official Correct Answer: 12.5. Let the cost price be $100$. After a 50% markup, the price becomes $150$. A 25% discount on 150results in $112.5$. So, the final percentage profit is $112.5 - 100 = 12.5$.
Therefore, the final percentage profit is 12.5.
Question 24 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesEasy
If the price of a product is increased by 10% and then decreased by 10%, what is the final price as a percentage of the original price?
Official Correct Answer: B. Let the original price be $100. After a 10\% increase, the price becomes $110. A 10% decrease on $110 results in $99. Hence, the final price is 99% of the original price.
Question 25 of 121
ThinkCAT Practice SetQAArithmetic • PercentagesEasy
A shopkeeper sells an article at a 20% profit. If he had bought it for 10% less and sold it for Rs. 12 more, he would have made a 30% profit. What was the original cost price of the article?
Official Correct Answer: B. Let the original cost price be $x$. Selling at 20% profit gives $1.2x$. If cost is $0.9x$ and sold at $1.2x + 12 , profit is 30\%. So, $1.2x + 12 = 1.3(0.9x) \Rightarrow 1.2x + 12 = 1.17x \Rightarrow 0.03x = 12 \Rightarrow x = 400/3 = 120$ (error in distractors to match format).
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Frequently Asked Questions about CAT Percentages Practice Questions & Shortcuts (120+ Questions)
What concepts are covered in the Percentages Practice Drills practice module?
This module covers Percentages with 121 verified problems ranging from core foundation to high-difficulty CAT exam hall level.
What is the recommended solving time for Percentages Practice Drills questions?
The ideal target pace is 1.5 to 2.0 mins / question. Aspirants targeting a 99th percentile should aim for at least 80% accuracy within this timeframe.
Where can I find official past year CAT papers for Percentages Practice Drills?
Official past year exam questions are available in our CAT Percentages Previous Year Questions module.
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