📌 Core Concept
To determine the number of positive integers up to 500 with non-repeating digits, we consider numbers with 1, 2, or 3 digits. For each category, we calculate the count of numbers with unique digits.
🔢 Step-by-Step Solution
1
One-digit numbers (1 to 9):
All one-digit numbers have non-repeating digits.
2
Two-digit numbers (10 to 99):
Tens place: 9 options (1-9)
Units place: 9 options (0-9 excluding the tens digit)
Count:
9×9=81
3
Three-digit numbers (100 to 499):
Hundreds place: 4 options (1-4)
Tens place: 9 options (0-9 excluding the hundreds digit)
Units place: 8 options (0-9 excluding the hundreds and tens digits)
Count:
4×9×8=288
Sum of one-digit, two-digit, and three-digit counts.
Total:
9+81+288=378
⚡ 30-Second Shortcut
Three-digit: 4 × 9 × 8 = 288$.
Total: 9 + 81 + 288 = 378$.
🎯 Final Answer
Correct Answer: 378