Data Interpretation • DI Multi-Source Caselets Practice Drills (33 Qs) Official Answer Keys

CAT DI Multi-Source Caselets Practice Questions (30+ Questions)

Paragraph-Based Data Caselets, Multi-Condition Financial Statements, and Logical Quantitative Reasoning

33 Total Questions
MCQ: 8 (+3 / -1)
TITA: 25 (0 Negative Penalty)

Core Formulas & Shortcut Matrix: DI Multi-Source Caselets Practice Drills

Index Number RelativitiesFormula #1
\text{Index} = \frac{\text{Current Period Value}}{\text{Base Period Value}} × 100

Standard relative benchmarking.

Exam Hall Traps & Speedbreakers to Avoid
  • Starting calculations before converting all text figures into a unified summary table.

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Official Exam Questions & Explanations (25 of 33)

Sorted in official convenor sequence
Question 1 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryModerate
In a town, there are 100 people. 40 people like coffee, 50 like tea, and 15 like both. How many people like neither coffee nor tea?
Official Correct Answer: B. Using the principle of inclusion-exclusion, the number of people who like either coffee or tea or both is 40 + 50 - 15 = 75. Therefore, the number of people who like neither is 100 - 75 = 25.
Question 2 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryModerate
A club has 60 members. 30 members like basketball, 25 like cricket, and 10 like both. How many members like either basketball or cricket or both?
Official Correct Answer: B. Using the principle of inclusion-exclusion, the number of members who like either basketball or cricket or both is 30 + 25 - 10 = 45.
Question 3 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryModerate
A group has 80 members. 45 members like novels, 35 like comics, and 20 like both. How many members like either novels or comics but not both?
Official Correct Answer: A. The number of members who like only novels is 45 - 20 = 25, and the number who like only comics is 35 - 20 = 15. Therefore, the number who like either but not both is 25 + 15 = 40.
Question 4 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryModerate
A club has 120 members. 70 members like basketball, 50 like cricket, and 30 like both. How many members like only basketball?
Official Correct Answer: A. The number of members who like only basketball is 70 - 30 = 40.
Question 5 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryModerate
A company has 150 employees. 90 employees use Windows, 70 use Linux, and 30 use both. How many employees use neither Windows nor Linux?
Official Correct Answer: A. The number of employees who use either Windows or Linux or both is 90 + 70 - 30 = 130. Therefore, the number who use neither is 150 - 130 = 20.
Question 6 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryModerate
A club has 180 members. 100 members like basketball, 80 like cricket, and 40 like both. How many members like only basketball?
Official Correct Answer: A. The number of members who like only basketball is 100 - 40 = 60.
Question 7 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryModerate
In a school, 150 students are enrolled. 80 students take mathematics, 70 take science, and 30 take both. How many students take only mathematics?
TITA Answer:
Official Correct Answer: 50. The number of students who take only mathematics is 80 - 30 = 50.
Question 8 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryModerate
If 15 students liked only Chemistry, how many students liked exactly two subjects?
TITA Answer:
Official Correct Answer: 35. Students liking only Chemistry is 15, and total liking Chemistry is 20. Thus, those liking Chemistry and another subject (but not all three) is 20 - 15 - 5 = 10. Adding those liking Mathematics and Chemistry but not Physics and those liking Physics and Chemistry but not Mathematics, we get 20 - 5 - 10 = 5. Hence, 10 + 5 + 10 = 35.
Question 9 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryModerate
If 5 students liked all three subjects, how many students liked only one subject?
Official Correct Answer: B) 40. Total students is 100. Students liking all three subjects is 5. Subtracting those from each subject, we get 55 - 5 = 50 for only Mathematics, 45 - 5 = 40 for only Physics, and 15 - 5 = 10 for only Chemistry. Hence, 50 + 40 + 10 = 100 - 5 = 95, and those liking only one subject is 40.
Question 10 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryModerate
If 10 students liked both Mathematics and Chemistry but not Physics, how many students liked only Physics?
TITA Answer:
Official Correct Answer: 20. Students liking both Mathematics and Chemistry but not Physics is 10. Subtracting this from the total liking Mathematics and Chemistry, we get 20 - 10 = 10. Hence, those liking only Physics and not Mathematics or Chemistry is 50 - (10 + 5 + 15) = 20.
Question 11 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryModerate
If 10 students liked both Mathematics and Physics but not Chemistry, how many students liked only Chemistry?
TITA Answer:
Official Correct Answer: 15. Students liking both Mathematics and Physics but not Chemistry is 10. Subtracting this from the total liking Mathematics and Physics, we get 50 - 10 = 40. Hence, those liking only Chemistry and not Mathematics or Physics is 20 - (40 - 10) - 5 = 15.
Question 12 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryModerate
If 20 students liked only Mathematics, how many students liked either Mathematics or Physics but not Chemistry?
TITA Answer:
Official Correct Answer: 50. Students liking only Mathematics is 20. Subtracting those from the total liking Mathematics, we get 60 - 20 = 40. Adding those liking only Physics and not Chemistry, we get 50 - (40 - 20) - 5 = 35. Hence, 40 + 15 = 55 - 5 = 50.
Question 13 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryModerate
If 15 students liked only Chemistry, how many students liked either Mathematics or Chemistry but not Physics?
TITA Answer:
Official Correct Answer: 50. Students liking only Chemistry is 15. Subtracting those from the total liking Chemistry, we get 20 - 15 = 5. Hence, those liking either Mathematics or Chemistry but not Physics is 60 - 15 - 10 = 35 + 5 = 40.
Question 14 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryHard
A group of 150 students is surveyed about their preferences for three subjects: Mathematics, Physics, and Chemistry. 80 students like Mathematics, 70 like Physics, and 60 like Chemistry. 30 students like both Mathematics and Physics, 25 like both Physics and Chemistry, and 20 like both Chemistry and Mathematics. If 10 students like all three subjects, how many students like exactly one subject?
Official Correct Answer: B. Using the principle of inclusion-exclusion, the total is given by $80 + 70 + 60 - (30 + 25 + 20) + 10 = 150$. Let $x , y , and $z$ be the number of students who like exactly one subject. The equation simplifies to $x + 2(30 + 25 + 20 - 3*10) + 10 = 150 , leading to $x = 50$.
Question 15 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryHard
A group of 250 students is surveyed about their interest in three sports: Cricket, Football, and Basketball. 100 like Cricket, 90 like Football, and 80 like Basketball. 40 like both Cricket and Football, 30 like both Football and Basketball, and 25 like both Cricket and Basketball. If 15 students like all three sports, how many like exactly one sport?
TITA Answer:
Official Correct Answer: 80. Using the principle of inclusion-exclusion, the total is given by $100 + 90 + 80 - (40 + 30 + 25) + 15 = 250$. Let $x$ be the number of students who like exactly one sport. Then, $x + 2(40 + 30 + 25 - 3*15) + 15 = 250 , leading to $x = 80$.
Question 16 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryHard
A survey of 200 participants includes 120 who prefer tea, 100 who prefer coffee, and 80 who prefer juice. 50 like both tea and coffee, 30 like both coffee and juice, and 20 like both tea and juice. If 10 like all three, how many like exactly one preference?
TITA Answer:
Official Correct Answer: 50. Using the principle of inclusion-exclusion, the total is given by $120 + 100 + 80 - (50 + 30 + 20) + 10 = 200$. Let $x$ be the number of participants who like exactly one preference. Then, $x + 2(50 + 30 + 20 - 3*10) + 10 = 200 , leading to $x = 50$.
Question 17 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryHard
A group of 250 students is asked about their preference for three subjects: mathematics, physics, and chemistry. 120 like mathematics, 100 like physics, and 80 like chemistry. 50 like both mathematics and physics, 30 like both physics and chemistry, and 25 like both mathematics and chemistry. If 15 like all three, how many like exactly one subject?
TITA Answer:
Official Correct Answer: 80. Using the principle of inclusion-exclusion, the total is given by $120 + 100 + 80 - (50 + 30 + 25) + 15 = 250$. Let $x$ be the number of students who like exactly one subject. Then, $x + 2(50 + 30 + 25 - 3*15) + 15 = 250 , leading to $x = 80$.
Question 18 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryHard
A group of 300 students is surveyed about their interest in three sports: cricket, football, and basketball. 150 like cricket, 120 like football, and 100 like basketball. 60 like both cricket and football, 45 like both football and basketball, and 35 like both cricket and basketball. If 30 like all three sports, how many like exactly one sport?
TITA Answer:
Official Correct Answer: 105. Using the principle of inclusion-exclusion, the total is given by $150 + 120 + 100 - (60 + 45 + 35) + 30 = 300$. Let $x$ be the number of students who like exactly one sport. Then, $x + 2(60 + 45 + 35 - 3*30) + 30 = 300 , leading to $x = 105$.
Question 19 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryHard
A survey of 200 participants includes 110 who prefer tea, 90 who prefer coffee, and 80 who prefer juice. 40 like both tea and coffee, 30 like both coffee and juice, and 25 like both tea and juice. If 15 like all three, how many like exactly one preference?
TITA Answer:
Official Correct Answer: 55. Using the principle of inclusion-exclusion, the total is given by $110 + 90 + 80 - (40 + 30 + 25) + 15 = 200$. Let $x$ be the number of participants who like exactly one preference. Then, $x + 2(40 + 30 + 25 - 3*15) + 15 = 200 , leading to $x = 55$.
Question 20 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryHard
A survey was conducted on 150 people. 90 like chocolate, 75 like vanilla, and 40 like both. How many people like either chocolate or vanilla but not both?
TITA Answer:
Official Correct Answer: 45. Using the principle of inclusion-exclusion, the number of people who like either chocolate or vanilla is $90 + 75 - 40 = 125$. Therefore, the number of people who like either chocolate or vanilla but not both is $125 - 40 = 85 - 40 = 45$.
Question 21 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryHard
In a class of 100 students, 60 are good at Mathematics, 50 are good at Physics, and 30 are good at both. How many students are good at either Mathematics or Physics but not both?
TITA Answer:
Official Correct Answer: 40. Using the principle of inclusion-exclusion, the number of students who are good at either Mathematics or Physics is $60 + 50 - 30 = 80$. Therefore, the number of students who are good at either Mathematics or Physics but not both is $80 - 30 = 50 - 30 = 40$.
Question 22 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryEasy
A group of 150 students consists of 90 girls and 60 boys. If 30 students are selected at random, how many girls are expected to be selected?
TITA Answer:
Official Correct Answer: 18. The expected number of girls is the proportion of girls in the group multiplied by the total number of students selected, i.e., (90/150) * 30 = 18.
Question 23 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryModerate
In a class of 120 students, 80 students are good at mathematics, 70 are good at physics, and 40 are good at both. How many students are good at either mathematics or physics?
TITA Answer:
Official Correct Answer: 110. Using the principle of inclusion-exclusion, the number of students good at either mathematics or physics is 80 + 70 - 40 = 110.
Question 24 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryHard
A club has 150 members. 90 members like basketball, 80 like football, and 50 like both. How many members like neither?
TITA Answer:
Official Correct Answer: 30. The number of members who like either or both sports is 90 + 80 - 50 = 120. Therefore, 150 - 120 = 30 members like neither.
Question 25 of 33
ThinkCAT Practice SetDILRData InterpretationSet TheoryEasy
In a group of 120 people, 80 like chocolate, 70 like vanilla, and 30 like both. How many people like neither?
TITA Answer:
Official Correct Answer: 20. The number of people who like either or both is 80 + 70 - 30 = 120. Therefore, 120 - 120 = 0 people like neither.

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Frequently Asked Questions about CAT DI Multi-Source Caselets Practice Questions (30+ Questions)

What concepts are covered in the DI Multi-Source Caselets Practice Drills practice module?

This module covers Set Theory with 33 verified problems ranging from core foundation to high-difficulty CAT exam hall level.

What is the recommended solving time for DI Multi-Source Caselets Practice Drills questions?

The ideal target pace is 10 to 12 mins / caselet. Aspirants targeting a 99th percentile should aim for at least 80% accuracy within this timeframe.

Where can I find official past year CAT papers for DI Multi-Source Caselets Practice Drills?

Official past year exam questions are available in our CAT Data Interpretation PYQ Hub module.

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