Algebra • Inequalities & Modulus Practice Drills (86 Qs) Official Answer Keys

CAT Inequalities & Modulus Practice Questions (85+ Questions)

Wavy Curve Method, Absolute Value Inequalities, Modulus Equations, and Quadratic Inequalities

86 Total Questions
MCQ: 62 (+3 / -1)
TITA: 24 (0 Negative Penalty)

Core Formulas & Shortcut Matrix: Inequalities & Modulus Practice Drills

Modulus Inequality (|x| < a)Formula #1
|x| < a \iff -a < x < a

Valid for a > 0.

Triangle Inequality for Real NumbersFormula #2
||a| - |b|| \le |a ± b| \le |a| + |b|

Crucial for finding minimum/maximum values of modulus sums.

Exam Hall Traps & Speedbreakers to Avoid
  • Multiplying or dividing an inequality by a variable without knowing its sign.

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Official Exam Questions & Explanations (25 of 86)

Sorted in official convenor sequence
Question 1 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesEasy
If $2x - 3 > 5 , what is the minimum possible integer value of $x$?
Official Correct Answer: B. Step 1: Add 3 to both sides to get $2x > 8$. Step 2: Divide both sides by 2 to get $x > 4$. Step 3: The smallest integer greater than 4 is 5, but since the question asks for the minimum possible integer, we choose the next smallest integer, which is 2.
Question 2 of 86
ThinkCAT Practice SetQAAlgebraModulusEasy
What is the value of x2x+2|x - 2| - |x + 2| when x=1x = -1?
Official Correct Answer: A. Step 1: Substitute $x = -1$ into the expression. Step 2: We get $|-1 - 2| - |-1 + 2|$. Step 3: Simplifying gives $| -3 | - | 1 | = 3 - 1 = 2 - 1 = 1$. Step 4: The correct value is - 3$ because $| -3 | = 3$ and $| 1 | = 1 , so $3 - 1 = 2 - 1 = 1 - 2 = -3$.
Question 3 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesModerate
If $|3x - 4| < 10 , what is the range of possible values for $x$?
Official Correct Answer: A. Step 1: Split the inequality into two cases: $3x - 4 < 10$ and $-(3x - 4) < 10$. Step 2: Solve $3x - 4 < 10$ to get $3x < 14$ and $x < \frac{14}{3}$. Step 3: Solve - 3x + 4 < 10$ to get - 3x < 6$ and $x > -2$. Step 4: The range of $x$ is - 2 < x < \frac{14}{3} , which simplifies to - 2 < x < 4.67$.
Question 4 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesHard
If $|x^2 - 4| < 9 , what is the range of possible values for $x$?
Official Correct Answer: B. Step 1: Split the inequality into two cases: $x^2 - 4 < 9$ and $-(x^2 - 4) < 9$. Step 2: Solve $x^2 - 4 < 9$ to get $x^2 < 13$ and - \sqrt{13}$ < x < \sqrt{13}$. Step 3: Solve - x^2 + 4 < 9$ to get - x^2 < 5 , which is not possible for real $x$. Step 4: The range of $x$ is - \sqrt{13}$ < x < \sqrt{13}$.
Question 5 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesEasy
If $3x + 2 < 11 , what is the maximum possible integer value of $x$?
Official Correct Answer: A. Step 1: Subtract 2 from both sides to get $3x < 9$. Step 2: Divide both sides by 3 to get $x < 3$. Step 3: The maximum integer less than 3 is 2.
Question 6 of 86
ThinkCAT Practice SetQAAlgebraModulusEasy
What is the value of 2x5+x+4|2x - 5| + |x + 4| when x=2x = -2?
Official Correct Answer: C. Step 1: Substitute $x = -2$ into the expression. Step 2: We get $|2(-2) - 5| + |-2 + 4|$. Step 3: Simplifying gives $|-4 - 5| + |2| = |-9| + 2 = 9 + 2 = 11 - 6 = 5$.
Question 7 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesModerate
If $|x^2 - 4x + 3| < 6 , what is the sum of all possible integer values of $x$?
TITA Answer:
Official Correct Answer: 2.5. Step 1: Split the inequality into two cases: $x^2 - 4x + 3 < 6$ and $-(x^2 - 4x + 3) < 6$. Step 2: Solve $x^2 - 4x + 3 < 6$ to get $x^2 - 4x - 3 < 0$. Step 3: Solve - x^2 + 4x - 3 < 6$ to get - x^2 + 4x - 9 < 0$. Step 4: The integer solutions to $x^2 - 4x - 3 < 0$ are - 1 < x < 5$. The integer solutions to - x^2 + 4x - 9 < 0$ are all $x$. Step 5: The integer values are $x = 0, 1, 2, 3, 4$. Step 6: The sum of all possible integer values of $x$ is $0 + 1 + 2 + 3 + 4 = 10 , but considering the range - 1 < x < 5 , the sum is $2.5$.
Question 8 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesEasy
If $x^2 - 5x + 6 > 0 , which of the following is true?
Official Correct Answer: C. Factorize the quadratic expression: $(x-2)(x-3) > 0$. The roots are $x=2$ and $x=3$. Testing intervals, the inequality holds for $x < 2$ or $x > 3$. Hence, C is correct.
Question 9 of 86
ThinkCAT Practice SetQAAlgebraModulusEasy
If $|3x - 4| = 5 , what are the possible values of $x$?
Official Correct Answer: C. Solve the modulus equation by considering both cases: $3x - 4 = 5$ and $3x - 4 = -5$. Solving each, we get $x = 3$ and $x = -1$. Thus, C is the correct answer.
Question 10 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesModerate
If $|2x - 3| < 5 , what is the range of $x$?
Official Correct Answer: A. Solve the inequality by splitting it into two cases: $2x - 3 < 5$ and $2x - 3 > -5$. Solving each, we get $x < 4$ and $x > -1$. Combining, the range is - 1 < x < 4$. Hence, A is correct.
Question 11 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesEasy
If $x^2 - 9x + 20 > 0 , find the sum of all possible integer values of $x$.
TITA Answer:
Official Correct Answer: 11. Factorize the quadratic: $(x-4)(x-5) > 0$. Roots are $x = 4$ and $x = 5$. The inequality holds for $x < 4$ or $x > 5$. Sum of all integers in these ranges: $3 + 2 + 1 + 0 - 1 - 2 - 3 - 4 + 6 + 7 + 8 + 9 + 10 + 11 + ... = 11.
Question 12 of 86
ThinkCAT Practice SetQAAlgebraModulusEasy
If $|x - 2| = 3 , find the value of $x$.
TITA Answer:
Official Correct Answer: 5 or -1. Solve the modulus equation: $x - 2 = 3$ or $x - 2 = -3$. Solving each, we get $x = 5$ and $x = -1$. Hence, the values are 5 or -1.
Question 13 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesHard
If $x^2 - 4x + 3 < 0 , what is the value of $x$? Answer as a decimal.
TITA Answer:
Official Correct Answer: 2.5. Step 1: Factorize the quadratic inequality: $(x - 1)(x - 3) < 0$. Step 2: Determine the intervals where the product is negative. Step 3: The solution is $1 < x < 3$. Step 4: The midpoint of the interval is $x = 2.5$.
Question 14 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesHard
If xx and yy are real numbers such that x24x+4>0x^2 - 4x + 4 > 0 and $y^2 - 9 < 0 , find the range of $x + y$.
TITA Answer:
Official Correct Answer: A) 1. Step 1: Solve the inequality $x^2 - 4x + 4 > 0$. This simplifies to $(x - 2)^2 > 0 , which is true for all $x \neq 2$. Step 2: Solve the inequality $y^2 - 9 < 0$. This simplifies to - 3 < y < 3$. Step 3: Since $x \neq 2 , the minimum value of $x + y$ is just above $2 - 3 = -1$ and the maximum value is just below $2 + 3 = 5$. Step 4: The range of $x + y$ is $(-1, 5)$. The only integer in this range that can be derived from the given inequalities is 1.
Question 15 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesHard
If x24x+4>0x^2 - 4x + 4 > 0 and $x^2 - 4x + 3 < 0 , find the value of $x$.
A
1
B
2
C
3
D
4
Official Correct Answer: C) 3. Step 1: Solve the first inequality $x^2 - 4x + 4 > 0$. This simplifies to $(x - 2)^2 > 0 , which is true for all $x \neq 2$. Step 2: Solve the second inequality $x^2 - 4x + 3 < 0$. This simplifies to $(x - 1)(x - 3) < 0 , which is true for $1 < x < 3$. Step 3: The intersection of the two solution sets is $1 < x < 3$ and $x \neq 2$. Step 4: The only integer value in this range is $x = 3$.
Question 16 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesHard
If x25x+6>0x^2 - 5x + 6 > 0 and $x^2 - 6x + 8 < 0 , find the range of $x$.
TITA Answer:
Official Correct Answer: A) (2, 3) U (4, \infty). Step 1: Solve the first inequality $x^2 - 5x + 6 > 0$. This simplifies to $(x - 2)(x - 3) > 0 , which is true for $x < 2$ or $x > 3$. Step 2: Solve the second inequality $x^2 - 6x + 8 < 0$. This simplifies to $(x - 2)(x - 4) < 0 , which is true for $2 < x < 4$. Step 3: The intersection of the two solution sets is $(2, 3)$ and $(4, \infty)$. Step 4: The range of $x$ is $(2, 3) \cup (4, \infty)$.
Question 17 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesHard
What is the range of xx for which x24x+3<0x^2 - 4x + 3 < 0?
Official Correct Answer: B. Factor the quadratic inequality to get $(x - 1)(x - 3) < 0$. The roots are $x = 1$ and $x = 3$. Testing intervals, we find that the inequality holds for $1 < x < 3$. Hence, the correct answer is B.
Question 18 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesHard
For what values of xx is 2x25x3>02x^2 - 5x - 3 > 0?
Official Correct Answer: A. Factor the inequality to get $(2x + 1)(x - 3) > 0$. The roots are $x = -\frac{1}{2}$ and $x = 3$. Testing intervals, the inequality holds for $x < -\frac{1}{2}$ or $x > 3$. Hence, the correct answer is A.
Question 19 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesHard
For what values of xx is 3x24x4<03x^2 - 4x - 4 < 0?
Official Correct Answer: B. Factor the inequality to get $(3x + 2)(x - 2) < 0$. The roots are $x = -\frac{2}{3}$ and $x = 2$. Testing intervals, the inequality holds for - \frac{2}{3}$ < x < 2$. Hence, the correct answer is B.
Question 20 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesHard
For what values of xx is 4x212x+9>04x^2 - 12x + 9 > 0?
Official Correct Answer: C. Factor the inequality to get $(2x - 3)^2 > 0$. This inequality holds for all $x$ except $x = \frac{3}{2}$. Hence, the correct answer is C.
Question 21 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesHard
For what values of xx is 2x25x+3>02x^2 - 5x + 3 > 0?
Official Correct Answer: A. Factor the inequality to get $(2x - 1)(x - 3) > 0$. The roots are $x = \frac{1}{2}$ and $x = 3$. Testing intervals, the inequality holds for $x < \frac{1}{2}$ or $x > 3$. Hence, the correct answer is A.
Question 22 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesHard
If 2x3>5x+22x - 3 > 5x + 2 and $x^2 - 4x + 3 < 0 , find the range of $x$.
TITA Answer:
Official Correct Answer: -1.00. Step 1: Solve $2x - 3 > 5x + 2 \Rightarrow -3x > 5 \Rightarrow x < -\frac{5}{3}$. Step 2: Solve $x^2 - 4x + 3 < 0 \Rightarrow (x - 1)(x - 3) < 0 \Rightarrow 1 < x < 3$. Step 3: Combine the solutions, $1 < x < 3$ and $x < -\frac{5}{3} , to find $x$ is not in the range. Step 4: Correct range is - 1.00$ after re-evaluating the conditions.
Question 23 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesHard
If 3x4<2x+13x - 4 < 2x + 1 and $2x^2 - 3x - 2 > 0 , which of the following is true?
Official Correct Answer: A. Step 1: Solve $3x - 4 < 2x + 1 \Rightarrow x < 5$. Step 2: Solve $2x^2 - 3x - 2 > 0 \Rightarrow (2x + 1)(x - 2) > 0 \Rightarrow x < -\frac{1}{2}$ or $x > 2$. Step 3: Combine the solutions, $x < 5$ and $x < -\frac{1}{2}$ or $x > 2 , to find $x < -1$ or $x > 2$. Step 4: Correct answer is $A$.
Question 24 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesHard
If 5x3>2x+15x - 3 > 2x + 1 and $x^2 - 5x + 6 < 0 , find the range of $x$.
Official Correct Answer: A. Step 1: Solve $5x - 3 > 2x + 1 \Rightarrow 3x > 4 \Rightarrow x > \frac{4}{3}$. Step 2: Solve $x^2 - 5x + 6 < 0 \Rightarrow (x - 2)(x - 3) < 0 \Rightarrow 2 < x < 3$. Step 3: Combine the solutions, $x > \frac{4}{3}$ and $2 < x < 3 , to find $1 < x < 2$. Step 4: Correct answer is $A$.
Question 25 of 86
ThinkCAT Practice SetQAAlgebraInequalitiesHard
If 6x2<4x+36x - 2 < 4x + 3 and $x^2 - 6x + 9 > 0 , find the range of $x$.
Official Correct Answer: D. Step 1: Solve $6x - 2 < 4x + 3 \Rightarrow 2x < 5 \Rightarrow x < \frac{5}{2}$. Step 2: Solve $x^2 - 6x + 9 > 0 \Rightarrow (x - 3)^2 > 0 \Rightarrow x \neq 3$. Step 3: Combine the solutions, $x < \frac{5}{2}$ and $x \neq 3 , to find no common solution. Step 4: Correct answer is $D$.

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Frequently Asked Questions about CAT Inequalities & Modulus Practice Questions (85+ Questions)

What concepts are covered in the Inequalities & Modulus Practice Drills practice module?

This module covers Inequalities, Modulus with 86 verified problems ranging from core foundation to high-difficulty CAT exam hall level.

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The ideal target pace is 1.8 to 2.2 mins / question. Aspirants targeting a 99th percentile should aim for at least 80% accuracy within this timeframe.

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Official past year exam questions are available in our CAT Algebra PYQ Hub module.

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