Q5. Arrangements
MCQ · +3 / −1
In which of the following years were there two or more contracts?
- A) 2015
- B) 2017
- C) 2018
- D) 2016
Correct Answer
A) 2015
Step-by-step solution
📌 Core Concept
Count of contracts = 8 (2 per institute, 2 per vendor). Fix each contract's vendor and years from the clues, then count contracts year by year.
🔢 Step-by-Step Solution
1
Fact 3 makes both W contracts single-year contracts in 2012. The other two single-year contracts are not W's.
2
Z needs a contract in all 10 years using two contracts. Only B's 7-year contract plus a 3- or 4-year contract reach 10 years, so Z = B's 7-year plus one more multi-year contract.
3
X must cover 2010-2015 (6 years). A single-year contract is too short (4+1 = 5), so X holds two multi-year contracts. The two remaining singles therefore go to Y, in 2010 and 2019 (Fact 3).
4
If Z held D's 4-year contract, X would hold A and C in 2010-12 and 2013-15. Clue 6 (C has no 2011 contract) then forces A = 2010-12 and C = 2013-15. That gives only 4 contracts in 2012, against Fact 4. So Z holds a 3-year contract and X holds D plus the other 3-year contract.
5
D has no 2010 contract (Fact 7) and X ends in 2015, so D-X = 2012-15 and the other X contract = 2010-12. Clue 6 rules out C for that one, so A-X = 2010-12 and C-Z is a 3-year contract. B-Z = 2010-16 and C-Z = 2017-19. The alternative B 2013-19 would put C in 2010-12, including 2011.
6
C needs a 2012 contract, so C-W = 2012. D's X contract already covers 2012, so D's other contract is Y in 2019. B's 7-year already covers 2012, so B-Y = 2010 and A-W = 2012.
7
Contracts per year: 2010: 3, 2011: 2, 2012: 5, 2013: 2, 2014: 2, 2015: 2, 2016: 1, 2017: 1, 2018: 1, 2019:
2
### Why Not the Others
2016, 2017 and 2018 each have only one contract (B-Z in 2016, C-Z in 2017 and 2018).
2015 has A-less X... precisely D-X and B-Z, so two contracts.
Correct Answer: A