CAT 2023 Slot 1 QA Question 13

Multiple choice (+3 / −1) · Arithmetic · Ratio, Proportion & Variation · Try it, then check the answer and solution below.

CAT 2023 Slot 1QAArithmetic • Ratio, Proportion & VariationEasy
The salaries of three friends Sita, Gita and Mita are initially in the ratio $5 : 6 : 7 , respectively. In the first year, they get salary hikes of 20%,25%20\% , 25\% and 20%,respectively.Inthesecondyear,SitaandMitagetsalaryhikesof20\% , respectively. In the second year, Sita and Mita get salary hikes of40\%andand25\% , respectively, and the salary of Gita becomes equal to the mean salary of the three friends. The salary hike of Gita in the second year is
Answer and solution

Answer: A) 26%26\%

📌 Core Concept
The problem involves understanding ratios, percentage increases, and mean calculations. The key formula used is the percentage increase formula:
New Salary=Original Salary×(1+Percentage Increase100)\text{New Salary} = \text{Original Salary} \times (1 + \frac{\text{Percentage Increase}}{100})
🔢 Step-by-Step Solution
1
Initial Salaries:
Let the initial salaries be 5x,6x,and5x , 6x , and7x$ for Sita, Gita, and Mita respectively.
2
First Year Hikes:
Sita: 5x×1.20=6x5x \times 1.20 = 6x
Gita: 6x×1.25=7.5x6x \times 1.25 = 7.5x
Mita: 7x×1.20=8.4x7x \times 1.20 = 8.4x
3
Second Year Hikes:
Sita: 6x×1.40=8.4x6x \times 1.40 = 8.4x
Mita: 8.4x×1.25=10.5x8.4x \times 1.25 = 10.5x
Gita: 7.5x×(1+y100)7.5x \times (1 + \frac{y}{100})
4
Mean Salary Calculation:
Mean = \frac{8.4x + 10.5x + 7.5x(1 + y100\frac{y}{100})}{3}$
5
Equation Setup:
7.5x(1+y100)=8.4x+10.5x+7.5x(1+y100)37.5x(1 + \frac{y}{100}) = \frac{8.4x + 10.5x + 7.5x(1 + \frac{y}{100})}{3}
6
Solving for yy:
Multiply both sides by 3: \(22.5x(1 + y100\frac{y}{100}$) = 18.9x + 7.5x(1 + \frac{y}{1

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