📌 Core Concept
The problem involves repeated replacement, where each time a fraction of the mixture is replaced. The concentration of the original component after multiple replacements can be calculated using the formula: $
Concentration after n replacements=(1−f)n where
f is the fraction replaced each time.
🔢 Step-by-Step Solution
1
Let the total volume be
T.
2
After first replacement (mixture P):
Fraction of coffee:
TT−x
Fraction of cocoa:
Tx
3
After second replacement (mixture Q):
Coffee removed:
TT−x×x
Cocoa removed:
Tx×x
Remaining coffee:
(T−x)−TT−x×x=(T−x)×(1−Tx)
Remaining cocoa:
x−Tx2+x=x×(1−Tx)+x
4
Given ratio in Q: Coffee:Cocoa = 16:9.
Coffee fraction =
2516$
Cocoa fraction =
259$
5
Using concentration formula:
Coffee concentration after two replacements:
(1−Tx)2=2516
Taking square root:
1−Tx=54
Thus,
Tx=51
6
Cocoa in P:
51T
Cocoa in Q:
259T
Ratio \frac{
51T}{
259T} =
95$
⚡ 30-Second Shortcut
Recognize the repeated replacement pattern. After two replacements, the concentration ratio leads directly to the fraction
51$ for each step. The ratio of cocoa in P to Q simplifies to $5:9$ by comparing their fractions.
🎯 Final Answer
Correct Answer: Option A