CAT 2023 Slot 3 QA Question 15

Type-in-the-answer (no negative marking) · Arithmetic · Ratio, Proportion & Variation · Try it, then check the answer and solution below.

CAT 2023 Slot 3QAArithmetic • Ratio, Proportion & VariationModerate
The number of coins collected per week by two coin-collectors AA and BB are In the ratio 3:43:4. If the total number of coins collected by AA in 5 weeks is a multiple of 7,andthetotalnumberofcoinscollectedby7 , and the total number of coins collected byBin3weeksisamultipleofin 3 weeks is a multiple of24 , then the minimum possible number of coins collected by AA in one week is
TITA Answer:
Answer and solution

Answer: 42

The number of coins collected per week by two coin-collectors AA and BB are in the ratio 3:43:4. Let the number of coins collected by AA in one week be 3k3k and by BB be 4k4k.
1
The total number of coins collected by AA in 5 weeks is 15k,whichmustbeamultipleof7.Therefore,15k , which must be a multiple of 7. Therefore,15kmustbedivisibleby7,implyingmust be divisible by 7, implyingk$ must be a multiple of 7.
2
The total number of coins collected by BB in 3 weeks is 12k,whichmustbeamultipleof24.Therefore,12k , which must be a multiple of 24. Therefore,12kmustbedivisibleby24,implyingmust be divisible by 24, implyingk$ must be even.
The smallest kk that satisfies both conditions is the least common multiple (LCM) of 7 and 2, which is 14. Thus, the minimum number of coins collected by AA in one week is 3k=3×14=423k = 3 \times 14 = 42.
🎯 Final Answer
The minimum possible number of coins collected by AA in one week is \boxed{42}.

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