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CAT 2018 Slot 2 DILR · Set 1 of 8Data InterpretationModerate DifficultyQ1–Q4 · 2 MCQ + 2 TITA

CAT 2018 Slot 2 DILR Set 1: Tables (4 Questions) with Solutions

The Tables set from the official CAT 2018 Slot 2 DILR paper: the caselet, all 4 questions, the official answer key and a step-by-step solution for each. 100% free, no sign-up.

The Set: Read the Caselet First

CAT 2018 Slot 2 DILR · Questions 1–4
The base exchange rate of a currency X with respect to a currency Y is the number of units of currency Y which is equivalent in value to one unit of currency X. Currency exchange outlets buy currency at buying exchange rates that are lower than base exchange rates, and sell currency at selling exchange rates that are higher than base exchange rates.
A currency exchange outlet uses the local currency L to buy and sell three international currencies A, B, and C, but does not exchange one international currency directly with another. The base exchange rates of A, B and C with respect to L are in the ratio 100:120:1. The buying exchange rates of each of A, B, and C with respect to L are 5% below the corresponding base exchange rates, and their selling exchange rates are 10% above their corresponding base exchange rates.
The following facts are known about the outlet on a particular day:
1
The amount of L used by the outlet to buy C equals the amount of L it received by selling C.
2
The amounts of L used by the outlet to buy A and B are in the ratio 5:3.
3
The amounts of L the outlet received from the sales of A and B are in the ratio 5:9.
4
The outlet received 88000 units of L by selling A during the day.
5
The outlet started the day with some amount of L, 2500 units of A, 4800 units of B, and 48000 units of C.
6
The outlet ended the day with some amount of L, 3300 units of A, 4800 units of B, and 51000 units of C.

In the exam this set competed with 7 others for 60 minutes. Budget about 8 minutes if you attempt it.

Q1. Tables

TITA · +3 / 0
How many units of currency A did the outlet buy on that day?
Correct Answer
1200
Step-by-step solution
📌 Core Concept
Write every rate as a multiple of one unknown base rate. Then use the change in A's stock, together with the facts about L spent and L received, to find that unknown.
🔢 Step-by-Step Solution
1
Let the base rates of A, B, C be 100k100k, 120k120k, kk. Buying rates are 0.950.95 times base and selling rates are 1.101.10 times base.
2
Fact 4: A sold for 88000 L at 110k110k per unit, so A units sold =88000110k=800k=\dfrac{88000}{110k}=\dfrac{800}{k}.
3
Fact 3: L received from B sales =88000×95=158400=88000\times\dfrac{9}{5}=158400.
4
Fact 5 and 6: B stock is unchanged at 4800, so B units bought equal B units sold. The L spent buying B is therefore 158400×0.951.10=136800158400\times\dfrac{0.95}{1.10}=136800.
5
Fact 2: L spent buying A =136800×53=228000=136800\times\dfrac{5}{3}=228000. At 95k95k per unit, A units bought =22800095k=2400k=\dfrac{228000}{95k}=\dfrac{2400}{k}.
6
A stock rose from 2500 to 3300, so bought −- sold =800=800. This gives 2400k−800k=800\dfrac{2400}{k}-\dfrac{800}{k}=800, so k=2k=2.
7
A units bought =24002=1200=\dfrac{2400}{2}=1200.
Quick Check
Base rate of A is 200 and the buying rate is 190. 1200×190=2280001200\times190=228000, which matches step 5.
Correct Answer: 1200

Q2. Tables

MCQ · +3 / −1
How many units of currency C did the outlet sell on that day?
  1. A) 22000
  2. B) 3000
  3. C) 6000
  4. D) 19000
Correct Answer
D) 19000
Step-by-step solution
📌 Core Concept
Fact 1 says the L spent buying C equals the L received from selling C. Combined with the change in C's stock, this fixes the units sold.
🔢 Step-by-Step Solution
1
Let the base rate of C be kk. The buying rate is 0.95k0.95k and the selling rate is 1.10k1.10k.
2
C stock rose from 48000 to 51000, so units bought −- units sold =3000=3000.
3
Let bb be the units bought and ss the units sold. Fact 1 gives 0.95k b=1.10k s0.95k\,b=1.10k\,s, so b=2219sb=\dfrac{22}{19}s.
4
Substitute into step 2: 2219s−s=3000\dfrac{22}{19}s-s=3000, so 319s=3000\dfrac{3}{19}s=3000 and s=19000s=19000.
Why Not the Others
A) 22000 is the number of units bought, not sold.
B) 3000 is only the net increase in C's stock.
C) 6000 has no basis in the data.
Quick Check
Units bought are 22000, and 0.95×22000=20900=1.10×190000.95\times22000=20900=1.10\times19000. This confirms fact 1.
Correct Answer: D

Q3. Tables

TITA · +3 / 0
What was the base exchange rate of currency B with respect to currency L on that day?
Correct Answer
240
Step-by-step solution
📌 Core Concept
Find the unknown scale factor of the base rates from A's stock change and the L flows. The base rate of B is then 120120 times that factor.
🔢 Step-by-Step Solution
1
Let the base rates of A, B, C be 100k100k, 120k120k, kk. Buying rates are 0.950.95 times base and selling rates are 1.101.10 times base.
2
Fact 4: A units sold =88000110k=800k=\dfrac{88000}{110k}=\dfrac{800}{k}.
3
Fact 3: L received from B sales =88000×95=158400=88000\times\dfrac{9}{5}=158400. B stock is unchanged, so B units bought equal B units sold, and L spent on B =158400×0.951.10=136800=158400\times\dfrac{0.95}{1.10}=136800.
4
Fact 2: L spent on A =136800×53=228000=136800\times\dfrac{5}{3}=228000. A units bought =22800095k=2400k=\dfrac{228000}{95k}=\dfrac{2400}{k}.
5
A stock rose by 3300−2500=8003300-2500=800, so 2400k−800k=800\dfrac{2400}{k}-\dfrac{800}{k}=800 and k=2k=2.
6
Base rate of B =120k=120×2=240=120k=120\times2=240.
Quick Check
Buying rate of B is 228228 and selling rate is 264264. The ratio 264228=1.100.95\dfrac{264}{228}=\dfrac{1.10}{0.95} matches the ratio used in step 3.
Correct Answer: 240

Q4. Tables

MCQ · +3 / −1
What was the buying exchange rate of currency C with respect to currency L on that day?
  1. A) 1.90
  2. B) 1.10
  3. C) 2.20
  4. D) 0.95
Correct Answer
A) 1.90
Step-by-step solution
📌 Core Concept
The buying rate of C is 5% below its base rate. So the base rate of C must be found first, from the scale factor kk that comes out of A's stock change.
🔢 Step-by-Step Solution
1
Let the base rates of A, B, C be 100k100k, 120k120k, kk. Buying rates are 0.950.95 times base and selling rates are 1.101.10 times base.
2
Fact 4: A units sold =88000110k=800k=\dfrac{88000}{110k}=\dfrac{800}{k}.
3
Fact 3: L received from B sales =158400=158400. B stock is unchanged, so L spent on B =158400×0.951.10=136800=158400\times\dfrac{0.95}{1.10}=136800.
4
Fact 2: L spent on A =136800×53=228000=136800\times\dfrac{5}{3}=228000. A units bought =22800095k=2400k=\dfrac{228000}{95k}=\dfrac{2400}{k}.
5
A stock rose by 800, so 2400k−800k=800\dfrac{2400}{k}-\dfrac{800}{k}=800 and k=2k=2. The base rate of C is 2.
6
Buying rate of C =0.95×2=1.90=0.95\times2=1.90.
Why Not the Others
B) 1.10 is the selling-rate multiplier, not a rate.
C) 2.20 is the selling rate of C, not the buying rate.
D) 0.95 is the buying multiplier, which would apply only if the base rate were 1.
Correct Answer: A
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CAT 2018 Slot 2 DILR at a Glance

Sets in this section8
Questions in this section32
Section time60 minutes
Convenor IIMIIM Calcutta

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