CAT 2024 Slot 2 QA Question 14

Multiple choice (+3 / −1) · Algebra · Modulus · Try it, then check the answer and solution below.

CAT 2024 Slot 2QAAlgebra • ModulusModerate
If x and y are real numbers such that ∣x∣+x+y=15|x| + x + y = 15 and x+∣y∣−y=20,thenx + |y| - y = 20 , then(x - y)$ equals
Answer and solution

Answer: C) 15

📌 Core Concept
The problem involves solving equations with absolute values. The key is to consider different cases based on the signs of the variables.
🔢 Step-by-Step Solution
1
First Equation:
∣x∣+x+y=15|x| + x + y = 15
Case 1: x ≥ 0$
2x+y=15(Equation 1a)2x + y = 15 \quad \text{(Equation 1a)}
Case 2: x < 0$
y=15(Equation 1b)y = 15 \quad \text{(Equation 1b)}
2
Second Equation:
x+∣y∣−y=20x + |y| - y = 20
Subcase 1a: y ≥ 0$
x=20(Contradictsy \geq0)x = 20 \quad \text{(Contradictsy \geq 0)}
Subcase 1b: y < 0$
x−2y=20(Equation 2a)x - 2y = 20 \quad \text{(Equation 2a)}
3
Solve Equations 1a and 2a:
{2x+y=15x−2y=20\begin{cases} 2x + y = 15 \\ x - 2y = 20 \end{cases}
Multiply Equation 1a by 2:
4x+2y=304x + 2y = 30
Add to Equation 2a:
\[ 5x = 50 \impl

Keep going

Related Modulus questions