Official Correct Answer: 2. ### Core Concept
The radius of the in-circle (inradius) of a triangle is given by the formula:
$$ r = \frac{A}{s} $$
where \( A \) is the area of the triangle and \( s \) is the semi-perimeter.
### Step-by-Step Solution
1. **Identify the Triangle Type and Calculate Sides**:
- The triangle has vertices at \( (1, 2) \), \( (7, 2) \), and \( (1, 10) \).
- Calculate side lengths using the distance formula:
- \( AB = \sqrt{(7-1)^2 + (2-2)^2} = 6 \)
- \( AC = \sqrt{(1-1)^2 + (10-2)^2} = 8 \)
- \( BC = \sqrt{(7-1)^2 + (2-10)^2} = 10 \)
- The triangle is right-angled with legs 6 and 8, and hypotenuse 10.
2. **Calculate the Area (A)**:
- For a right-angled triangle, area \( A = \frac{1}{2} \times \text{base} \times \text{height} \).
- \( A = \frac{1}{2} \times 6 \times 8 = 24 \).
3. **Calculate the Semi-Perimeter (s)**:
- \( s = \frac{a + b + c}{2} = \frac{6 + 8 + 10}{2} = 12 \).
4. **Compute the Inradius (r)**:
- \( r = \frac{A}{s} = \frac{24}{12} = 2 \).
### 30-Second Shortcut
For right-angled triangles, the inradius can be quickly calculated using:
$$ r = \frac{a + b - c}{2} $$
where \( c \) is the hypotenuse. Plugging in:
$$ r = \frac{6 + 8 - 10}{2} = \frac{4}{2} = 2 $$
### Final Answer
Correct Answer: 2
Answer and solution
Answer:2
📌Core Concept
The radius of the in-circle (inradius) of a triangle is given by the formula: $r=sA where A is the area of the triangle and s is the semi-perimeter.
🔢Step-by-Step Solution
1
Identify the Triangle Type and Calculate Sides:
The triangle has vertices at (1,2),(7,2),and(1, 10)$.
Calculate side lengths using the distance formula:
AB=(7−1)2+(2−2)2=6
AC=(1−1)2+(10−2)2=8
BC=(7−1)2+(2−10)2=10
The triangle is right-angled with legs 6 and 8, and hypotenuse 10.
2
Calculate the Area (A):
For a right-angled triangle, area A=21×base×height.
A=21×6×8=24.
3
Calculate the Semi-Perimeter (s):
s=2a+b+c=26+8+10=12.
4
Compute the Inradius (r):
r=sA=1224=2.
⚡30-Second Shortcut
For right-angled triangles, the inradius can be quickly calculated using: