CAT 2024 Slot 2 QA Question 9

Multiple choice (+3 / −1) · Algebra · Functions · Try it, then check the answer and solution below.

CAT 2024 Slot 2QAAlgebra • FunctionsHard
A function ff maps the set of natural numbers to whole numbers, such that f(xy)=f(x)f(y)+f(x)+f(y)f (xy) = f (x) f (y) + f (x) + f (y) for all x,yx, y and f(p)=1f (p) = 1 for every prime number pp. Then, the value of f(160000)f (160000) is
Answer and solution

Answer: C) 4095

📌 Core Concept & Formula
The function ff satisfies the property f(xy)=f(x)f(y)+f(x)+f(y)f(xy) = f(x)f(y) + f(x) + f(y) for all natural numbers xx and yy. By defining a new function g(x)=f(x)+1,wetransformthisintoamultiplicativefunction:g(x) = f(x) + 1 , we transform this into a multiplicative function:g(xy) = g(x)g(y).Foranyprime. For any primep , g(p) = 2$.
🔢 Step-by-Step Solution
1
Define the Function gg: Let g(x)=f(x)+1g(x) = f(x) + 1. Then, f(xy)+1=(f(x)+1)(f(y)+1),sof(xy) + 1 = (f(x) + 1)(f(y) + 1) , sog(xy) = g(x)g(y)$.
2
Prime Values: For any prime p,f(p)=1p , f(p) = 1 implies g(p)=2g(p) = 2.
3
Factorize 160000: 160000 = 2^8 × 5^4$.
4
Compute g(160000)g(160000): Since gg is multiplicative, \( g(1600

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