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CAT 2019 Slot 2 DILR · Set 8 of 8Logical ReasoningHard DifficultyQ29–Q32 · 4 MCQ

CAT 2019 Slot 2 DILR Set 8: Games & Tournaments (4 Questions) with Solutions

The Games & Tournaments set from the official CAT 2019 Slot 2 DILR paper: the caselet, all 4 questions, the official answer key and a step-by-step solution for each. 100% free, no sign-up.

The Set: Read the Caselet First

CAT 2019 Slot 2 DILR · Questions 29–32
Ten players, as listed in the table below, participated in a rifle shooting competition comprising of 10 rounds. Each round had 6 participants. Players numbered 1 through 6 participated in Round 1, players 2 through 7 in Round 2,..., players 5 through 10 in Round 5, players 6 through 10 and 1 in Round 6, players 7 through 10, 1 and 2 in Round 7 and so on.
The top three performances in each round were awarded 7, 3 and 1 points respectively. There were no ties in any of the 10 rounds. The table below gives the total number of points obtained by the 10 players after Round 6 and Round 10.
Player No.Player NamePoints after Round 6Points after Round 10
1Amita818
2Bala25
3Chen36
4David66
5Eric310
6Fatima1010
7Gordon1717
8Hansa14
9Ikea217
10Joshin1417
The following information is known about Rounds 1 through 6:
1
Gordon did not score consecutively in any two rounds.
2
Eric and Fatima both scored in a round.
The following information is known about Rounds 7 through 10:
1
Only two players scored in three consecutive rounds. One of them was Chen. No other player scored in any two consecutive rounds.
2
Joshin scored in Round 7, while Amita scored in Round 10.
3
No player scored in all the four rounds.

In the exam this set competed with 7 others for 60 minutes. Budget about 8 minutes if you attempt it.

Q29. Games & Tournaments

MCQ · +3 / −1
What were the scores of Chen, David, and Eric respectively after Round 3?
  1. A) 3, 6, 3
  2. B) 3, 0, 3
  3. C) 3, 3, 3
  4. D) 3, 3, 0
Correct Answer
C) 3, 3, 3
Step-by-step solution
📌 Core Concept
Each round awards exactly 7, 3 and 1 points. Use the totals after Round 6 together with the rule that only some players can reach certain values, and fix each player's scoring rounds one by one.
🔢 Step-by-Step Solution
1
Gordon (rounds 2 to 6) scored 17 with no two consecutive scoring rounds (Clue 1). The only fit is 7+7+3 in rounds 2, 4 and 6.
2
Joshin played only rounds 5 and 6 among the first six, so 14 means 7 in each. Round 6's 7 is taken, so Gordon got 3 in round 6 and 7 in rounds 2 and 4.
3
Amita (rounds 1 and 6) has 8 = 7+1. The 7 in round 6 is gone, so Amita scored 7 in round 1 and 1 in round 6.
4
Ikea has 2 and can score only in rounds 4 and 5 (round 6 is full), so Ikea got 1 in each. Hansa's single point must then come in round 3.
5
Gordon does not score in round 3. Of the remaining players, only Fatima (10) can hold a 7, so Fatima scored 7 in round 3.
6
Bala (2) played only rounds 1 and 2, so Bala got 1 in each. All six 1-point slots are now used, so Chen, David, Eric and Fatima scored only 3s: Chen one, Eric one, David two, Fatima one.
7
Clue 2 says Eric and Fatima scored in the same round. Each round has one 3, so this cannot be Fatima's 3. Eric's 3 therefore came in round 3, alongside Fatima's 7.
8
Fatima's other 3 can only be in round 5. David's second 3 is in round 4, leaving the round 1 and 2 3s for Chen and David, one each.
9
After round 3: Chen 3, David 3 (round 4 is later), Eric 3.
Why Not the Others
A: David cannot have 6 before round 4.
B and D: Eric's 3 came in round 3, and David already has a 3 from round 1 or 2.
Correct Answer: C

Q30. Games & Tournaments

MCQ · +3 / −1
Which three players were in the last three positions after Round 4?
  1. A) Bala, Ikea, Joshin
  2. B) Bala, Hansa, Ikea
  3. C) Hansa, Ikea, Joshin
  4. D) Bala, Chen, Gordon
Correct Answer
C) Hansa, Ikea, Joshin
Step-by-step solution
📌 Core Concept
Rebuild the round-by-round scores for rounds 1 to 4 from the totals after Round 6 and the given clues, then rank the players.
🔢 Step-by-Step Solution
1
Gordon (17, no consecutive scores) scored in rounds 2, 4 and 6. Joshin (14) scored 7 in rounds 5 and 6, so Gordon had 3 in round 6 and 7 in rounds 2 and 4.
2
Amita (8) scored 7 in round 1 and 1 in round 6, because round 6's 7 belongs to Joshin.
3
Ikea (2) can score only in rounds 4 and 5, so Ikea got 1 in each. Hansa (1) therefore scored 1 in round 3.
4
Round 3's 7 can only go to Fatima (10). Bala (2) played only rounds 1 and 2, so Bala got 1 in each.
5
All 1-point slots are now used, so Chen, David, Eric and Fatima scored only 3s. David (6) has two 3s, and Eric (3), Chen (3) and Fatima's second score are one 3 each. Eric shares round 3 with Fatima (Clue 2), so Eric's 3 is in round 3. Round 4's 3 goes to David, since Eric and Fatima are used up.
6
Totals after round 4: Gordon 14, Amita 7, Fatima 7, David 6, Chen 3, Eric 3, Bala 2, Hansa 1, Ikea 1, Joshin 0.
7
The three lowest are Joshin (0), then Hansa and Ikea (1 each).
Why Not the Others
A and B: Bala has 2, which is above Hansa and Ikea.
D: Chen and Gordon are well above the bottom (Gordon is the leader with 14).
Correct Answer: C

Q31. Games & Tournaments

MCQ · +3 / −1
Which player scored points in maximum number of rounds?
  1. A) Ikea
  2. B) Joshin
  3. C) Chen
  4. D) Amita
Correct Answer
A) Ikea
Step-by-step solution
📌 Core Concept
Points scored in rounds 7 to 10 equal (total after Round 10) minus (total after Round 6). Combine that with the round-by-round picture of rounds 1 to 6 and count each player's scoring rounds.
🔢 Step-by-Step Solution
1
Points in rounds 7 to 10: Amita 10, Bala 3, Chen 3, David 0, Eric 7, Fatima 0, Gordon 0, Hansa 3, Ikea 15, Joshin 3.
2
Ikea's 15 with at most four scores must be 7+7+1. Ikea plays rounds 7, 8 and 9 but not 10, so Ikea scored in all three, and is one of the two players with three consecutive scores. The other is Chen.
3
Chen's 3 over rounds 8, 9 and 10 (the only rounds of the four that Chen plays) must be 1+1+1. So Chen scored in 3 rounds there.
4
From rounds 1 to 6: Ikea scored 1 in rounds 4 and 5. Ikea's total is 2 + 3 = 5 scoring rounds.
5
Chen scored 3 once in round 1 or 2 and nowhere else in rounds 1 to 6 (total 3, a single 3, since the 1s are all taken). Chen's total is 1 + 3 = 4 rounds.
6
Amita scored in rounds 1, 6, 7 and 10, which is 4 rounds. Amita's rounds 7 to 10 are 7+3, since no 1+1+1+7 pattern is allowed.
7
Joshin scored in rounds 5, 6 and 7 for 3 rounds, with a single 3 in rounds 7 to 10.
8
Counts: Ikea 5, Chen 4, Amita 4, Joshin 3. Ikea scored in the most rounds.
Correct Answer: A

Q32. Games & Tournaments

MCQ · +3 / −1
Which players scored points in the last round?
  1. A) Amita, Chen, Eric
  2. B) Amita, Chen, David
  3. C) Amita, Bala, Chen
  4. D) Amita, Eric, Joshin
Correct Answer
A) Amita, Chen, Eric
Step-by-step solution
📌 Core Concept
Points in rounds 7 to 10 equal (total after Round 10) minus (total after Round 6). Work out who played and who scored in each round, then read off round 10.
🔢 Step-by-Step Solution
1
Points in rounds 7 to 10: Amita 10, Bala 3, Chen 3, David 0, Eric 7, Fatima 0, Gordon 0, Hansa 3, Ikea 15, Joshin 3.
2
Ikea's 15 must be 7+7+1. Ikea plays rounds 7 to 9 but not round 10, so Ikea scored in rounds 7, 8 and 9. Chen is the other player with three consecutive scoring rounds (Clue 1).
3
Chen plays only rounds 8, 9 and 10 among these, so Chen's 3 is 1+1+1 in rounds 8, 9 and 10.
4
Eric plays only round 10 in this stretch, so Eric's 7 came in round 10.
5
Amita scored in round 10 (Clue 2). Round 10 already has Eric 7 and Chen 1, so Amita got the 3.
6
Check: Amita's other 7 comes in round 7 (Ikea's 7 occupies round 8, and round 9 is consecutive with round 10). Joshin's 3 is in round 7, Hansa's 3 in round 8 and Bala's 3 in round 9. All totals and clues match.
7
The scorers in round 10 are Eric (7), Amita (3) and Chen (1).
Why Not the Others
B and C: David scored nothing in rounds 7 to 10, and Bala's only 3 came in round 9.
D: Joshin's only score in this stretch was in round 7.
Correct Answer: A
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CAT 2019 Slot 2 DILR at a Glance

Sets in this section8
Questions in this section32
Section time60 minutes
Convenor IIMIIM Kozhikode

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